Find Jobs
Hire Freelancers

Data manipulation: a simple but non-trivial project. (I require providing the source code in C++))

£20-250 GBP

Concluído
Publicado há quase 12 anos

£20-250 GBP

Pago na entrega
Please read carefully and understand the task. I included a simple example below. I have a datafile consisting of three columns (x, y, z). I would like to compare each set of (x,y), if two sets in the data are equal (up to ± 0.5) then I'd like to compare the two z columns. Here, I want to apply the following criteria: 1. If any z is outside the range (117 to118 && 122 to 128) then I'd like the row containing the z outside this range to be removed from the list of data (but be printed in another list containing the removed rows). 2. If the two z values lie within the previous range, then I would like the one farther from (125 ± 0.2) to be removed from the data. 3. If the two z values lie within (124±0.6) then keep both in the file. Of course, if there's a set of (x,y) that do not have any matches, then this set is to be kept in the file. Finally and more importantly, I'd like the source code in C/C++ for this somewhat straightforward task. Full payment will be made after receiving and testing this. To explain what I want exactly, here's an simplified version of what I want: Suppose we have this set of data (only two columns) 1 2 2 2 1 3 1 2 1 3 1 2 Then I say, if two rows start with the same number, then I only want the one which has the second column equal to 3. So when the program runs, it starts with the first row (1, 2), then compare it to the rest. Then it finds the row (1, 3). In this case both rows start with the same number 1. So now we compare the second column, and the action is to remove the row with second column less than 3 from the list of data (and it should be stored in another list). So as a result, the first row should go away, and we are left with 2 2 1 3 1 2 1 3 1 2 Then, row2 (2 2), which now becomes row1, is compared to the rest, but there's no other row starting with 2, so row2 is kept in the current list of data. then run the test for row (1, 3), after we've removed the first row (1, 2), is compared to the rest below it. As a result, we remove two rows with (1, 2) In the end, we should get a new data file with: 2 2 1 3 1 3 And another data file containing the removed rows 1 2 1 2 1 2 End of example. The only thing is that, in my case, I have x, y, z. I want to compare (x,y) and see if there's a match, if yes, then compare z, and apply the criteria I mentioned above. If no match (i.e. there's no other x,y that is equal to the one we are testing), then this row remains as it is in the file.
ID do Projeto: 2336846

Sobre o projeto

3 propostas
Projeto remoto
Ativo há 12 anos

Quer ganhar algum dinheiro?

Benefícios de ofertar no Freelancer

Defina seu orçamento e seu prazo
Seja pago pelo seu trabalho
Descreva sua proposta
É grátis para se inscrever e fazer ofertas em trabalhos
Concedido a:
Avatar do Usuário
Dear Hiring Manager I'm a expert in C,C++ and algorithm (please see my profile). I guarantee to complete your job well. Can i start? Best Regards, do-nhuan
£30 GBP em 1 dia
4,7 (3 avaliações)
2,8
2,8
3 freelancers estão ofertando em média £28 GBP for esse trabalho
Avatar do Usuário
Thank you for invitation. I can do it. Best regards, Tri
£30 GBP em 2 dias
4,7 (15 avaliações)
4,3
4,3
Avatar do Usuário
I am a regular member of online coding judges such as spoj where these type of problems are common. I will do your work within TIME LIMIT and most important ACCURATELY.
£25 GBP em 2 dias
5,0 (2 avaliações)
1,8
1,8

Sobre o cliente

Bandeira do(a) UNITED KINGDOM
Southampton, United Kingdom
5,0
1
Método de pagamento verificado
Membro desde fev. 14, 2012

Verificação do Cliente

Obrigado! Te enviamos um link por e-mail para que você possa reivindicar seu crédito gratuito.
Algo deu errado ao enviar seu e-mail. Por favor, tente novamente.
Usuários Registrados Total de Trabalhos Publicados
Freelancer ® is a registered Trademark of Freelancer Technology Pty Limited (ACN 142 189 759)
Copyright © 2024 Freelancer Technology Pty Limited (ACN 142 189 759)
Carregando pré-visualização
Permissão concedida para Geolocalização.
Sua sessão expirou e você foi desconectado. Por favor, faça login novamente.