Need JavaScript re-write for search of string

Simple job. Need this script re-written to test for any of the arguments provided, to be anywhere in the string generated from generateAddress() ([login to view URL]). Output should highlight in blue the same way. At the moment it just checks for the arguments to be at the start or finish. I want it to provide a match if any of the args are anywhere in the string. [login to view URL]('\x1b[36m%s\x1b[0m', 'Generator') [login to view URL]('\x1b[36m%s\x1b[0m', ' by @Me') [login to view URL]('') if ([login to view URL] > 0) { [login to view URL]('Looking for Strings with keywords at the start/end:') [login to view URL](function (k) { [login to view URL](' - ', k) }) var re = '^(c)(' + [login to view URL]('|') + ')(.+)$|^(c.+)(' + [login to view URL]('|') + ')$' [login to view URL](' ') [login to view URL]('testing regular expression: ') [login to view URL](' ', re) const regexp = new RegExp(re, 'i') [login to view URL]('') [login to view URL]('\x1b[33m%s\x1b[0m', '-- Press Control C to quit --'); [login to view URL]('') for (let i = 0;;i++) { account = [login to view URL](); var test = [login to view URL]([login to view URL]) if (test) { var address = '' if (test[1] === undefined) { address = test[4] + '\x1b[32m' + test[5] + '\x1b[0m' } else { address = test[1] + '\x1b[32m' + test[2] + '\x1b[0m' + test[3] } [login to view URL]("\n"); [login to view URL](' > Match: [ ' + address + ' ] with secret [ ' + [login to view URL] + ' ]') } else { if (i % 100 === 0) [login to view URL]('.') if (i % 1000 === 0) [login to view URL]("\r" + i + ' ') } } } else { [login to view URL]('Please enter one or more keywords after the script to search for.') [login to view URL]('Eg. "node ' + [login to view URL][1] + ' walter john bob"') [login to view URL]('') [login to view URL](0) }