c/c++ experience in hardware id based systems

Encerrado Postado há 6 anos Pago na entrega
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I'm looking for a smart c/c++ developer who has good experience with hardware id based systems. this work should be compatible with all windows operating systems even windows xp. You'll work with a friend of mine who is also c/c++ developer to create an impossible to bypass hardware id limit based system.

Programação C Programação C++

ID do Projeto: #13575652

Sobre o projeto

12 propostas Projeto remoto Ativo em há 6 anos

12 freelancers estão ofertando em média $681 nesse trabalho

LiangXiaoJin

Dear client, how are you? I am a C/C++ programmer and mathematician. No problem. Let's do. No problem. Let's do. No problem. Let's do. No problem. Let's do. No problem. Let's do. Please check my "Profile & Work Mais

$700 USD in 7 dias
(78 Comentários)
7.4
szymszteinsl

Hi! I am professional C/C++/C#/Java/Python programmer. I can do this project with highest quality! Best Regards, Szymszteinsl

$750 USD in 10 dias
(90 Comentários)
7.2
octopus823

Hi, I'm a OS expert experienced C/C++/ObjC developing. I already have done such tasks... I can develop almost kinds of C/C++/ObjC codes for any OS : Windows, Linux, MAC OS X... I can use almost of develop libraries Mais

$631 USD in 10 dias
(95 Comentários)
6.8
Klapaucius

Hi, do you wish to use HD id for copy protection or something else ? Which devices do you need to check - hdd, usb drives, CPU, motherboard ? The most common way is to do it with WMI calls, but in some older Windo Mais

$500 USD in 6 dias
(5 Comentários)
5.1
Tushibo

Hello. We have some earlier experience with Hardware ID generation and usage, among other things related to DRM implementation. For Windows platform the best approach (from out experience) is to hash info from WMI inte Mais

$555 USD in 10 dias
(0 Comentários)
0.0
rupaneeraj

Hello dear sir i have 8+ year of exp in c, C++ , i am also hardware engineer and i have done metlab and electeronics job. So pelase contact me for the job.

$555 USD in 10 dias
(1 Comentário)
0.0